The expression for solubility product of merc | vedclass

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Question

(D) The dissociation of mercurous iodide $(Hg_2I_2)$ in water is represented by the following equilibrium equation:$Hg_2I_2(s) \rightleftharpoons Hg_2

Vedclass · Accepted Answer

$[Hg_2^{2+}] [I^{-}]^2$

Vedclass · Answer

(D) The dissociation of mercurous iodide $(Hg_2I_2)$ in water is represented by the following equilibrium equation:$Hg_2I_2(s) \rightleftharpoons Hg_2^{2+}(aq) + 2I^{-}(aq)$Note that the mercurous ion exists as a dimer,$Hg_2^{2+}$.The solubility product constant $(K_{sp})$ is defined as the product of the molar concentrations of the ions,each raised to the power of its stoichiometric coefficient in the balanced chemical equation.Therefore,the expression for $K_{sp}$ is:$K_{sp} = [Hg_2^{2+}] [I^{-}]^2$Comparing this with the given options,the correct expression is represented by option $D$.

The expression for solubility product of mercurous iodide $(Hg_2I_2)$ is

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